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數線上的幾何求做法
Sep 17th 2013, 15:31

√(3+√5) +√(3-√5) =√a

==>√[(6+2√5)/2] +√[(6-2√5)/2]  =√a

分子分母同乘以2,其值不變
為配完全平方方式
如同根與係數關係
例:(a+b)+2√ab=(√a+√b)^2  ,a>0,b>0

==>√(√5 +1)^2/2  +√(√5 -1)^2/2=√a

==>(√5 +1)/√2  + (√5 -1)/√2=√a

==>2√5/√2=√a

==>√10=√a

==>a=10 

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